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Rd sharma solutions

CHAPTERS

6. Algebraic Expressions and Identities

8. Division of Algebraic Expressions

9. Linear Equation in One Variable

10. Direct and Inverse Variations

13. Profit Loss Discount and Value Added Tax

15. Understanding Shapes Polygons

16. Understanding Shapes Quadrilaterals

17. Understanding Shapes Special Types Quadrilaterals

20. Area of Trapezium and Polygon

21. Volume Surface Area Cuboid Cube

22. Surface Area and Volume of Right Circular Cylinder

23. Classification And Tabulation Of Data

24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs

A cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32 cm×22 cm×14 cm. Find the rise in the level of the water when the solid is completely submerged.

We have,

Diameter of base of cylindrical vessel = 56 cm

Radius of base = d/2 = 56/2 = 28cm

Dimensions of rectangular solid vessel = 32cm × 22cm × 14cm Volume of rectangular solid vessel = 32 × 22 × 14 = 9856 cm3

Let the rise of water level be ‘h’ cm

Volume of cylindrical container = Volume of rectangular solid vessel

πr2h = 9856

22/7 × 28 × 28 × h = 9856

h = 9856×7 / 22×28×28

= 68992 / 17248

= 4cm

∴ Rise in water level is 4cm.

Algebraic Expressions and Identities

Division of Algebraic Expressions

Linear Equation in One Variable

Profit Loss Discount and Value Added Tax

Understanding Shapes Quadrilaterals

Understanding Shapes Special Types Quadrilaterals

Volume Surface Area Cuboid Cube

Surface Area and Volume of Right Circular Cylinder

Classification And Tabulation Of Data

Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

Pictorial Representation Of Data As Pie Charts Or Circle Graphs

We have,

Diameter of base of cylindrical vessel = 56 cm

Radius of base = d/2 = 56/2 = 28cm

Dimensions of rectangular solid vessel = 32cm × 22cm × 14cm Volume of rectangular solid vessel = 32 × 22 × 14 = 9856 cm3

Let the rise of water level be ‘h’ cm

Volume of cylindrical container = Volume of rectangular solid vessel

πr2h = 9856

22/7 × 28 × 28 × h = 9856

h = 9856×7 / 22×28×28

= 68992 / 17248

= 4cm

∴ Rise in water level is 4cm.

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